An industrial waste flow of 0.075 MGD requires a chlorine dose of 8.5 mg/L. What should be the chlorinator setting?

To determine the appropriate chlorinator setting for an industrial waste flow of 0.075 million gallons per day (MGD) requiring a chlorine dose of 8.5 mg/L, it's essential to convert the flow and dosage into compatible units to calculate the required chlorine in pounds per 24 hours.

First, convert the flow rate from MGD to gallons per day:

0.075 MGD is equivalent to 75,000 gallons per day (since 1 MGD = 1,000,000 gallons).

Next, convert the chlorine dose from mg/L to pounds. The dose of 8.5 mg/L can be understood as 8.5 milligrams of chlorine per liter of water. Since there are approximately 3.78541 liters in a gallon, we can convert this into pounds:

1. First, convert the dose from mg/L to pounds per gallon. With 8.5 mg/L, since 1 mg = 0.00000220462 pounds:

• 8.5 mg/L * 0.00000220462 pounds/mg = 0.00001874 pounds/L.

2. Then, convert pounds per liter to pounds per gallon:

• 0.00001874 pounds/L